.7=9t^2

Solution for .7=9t^2 equation:

.7=9t^2

We move all terms to the left:

.7-(9t^2)=0

We add all the numbers together, and all the variables

-9t^2+0.7=0

a = -9; b = 0; c = +0.7;
Δ = b2-4ac
Δ = 02-4·(-9)·0.7
Δ = 25.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{25.2}}{2*-9}=\frac{0-\sqrt{25.2}}{-18}
=-\frac{\sqrt{}}{-18}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{25.2}}{2*-9}=\frac{0+\sqrt{25.2}}{-18}
=\frac{\sqrt{}}{-18}
$